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Fixed meanStdDev() implementation for the case input matrix has more than 4 channels
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@@ -306,14 +306,14 @@ static int sumsqr_(const T* src0, const uchar* mask, ST* sum, SQT* sqsum, int le
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if( !mask )
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{
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SumSqr_SIMD<T, ST, SQT> vop;
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int i = vop(src0, mask, sum, sqsum, len, cn), k = cn % 4;
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src += i * cn;
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int x = vop(src0, mask, sum, sqsum, len, cn), k = cn % 4;
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src = src0 + x * cn;
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if( k == 1 )
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{
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ST s0 = sum[0];
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SQT sq0 = sqsum[0];
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for( ; i < len; i++, src += cn )
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for(int i = x; i < len; i++, src += cn )
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{
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T v = src[0];
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s0 += v; sq0 += (SQT)v*v;
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@@ -325,7 +325,7 @@ static int sumsqr_(const T* src0, const uchar* mask, ST* sum, SQT* sqsum, int le
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{
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ST s0 = sum[0], s1 = sum[1];
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SQT sq0 = sqsum[0], sq1 = sqsum[1];
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for( ; i < len; i++, src += cn )
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for(int i = x; i < len; i++, src += cn )
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{
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T v0 = src[0], v1 = src[1];
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s0 += v0; sq0 += (SQT)v0*v0;
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@@ -338,7 +338,7 @@ static int sumsqr_(const T* src0, const uchar* mask, ST* sum, SQT* sqsum, int le
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{
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ST s0 = sum[0], s1 = sum[1], s2 = sum[2];
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SQT sq0 = sqsum[0], sq1 = sqsum[1], sq2 = sqsum[2];
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for( ; i < len; i++, src += cn )
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for(int i = x; i < len; i++, src += cn )
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{
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T v0 = src[0], v1 = src[1], v2 = src[2];
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s0 += v0; sq0 += (SQT)v0*v0;
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@@ -351,10 +351,10 @@ static int sumsqr_(const T* src0, const uchar* mask, ST* sum, SQT* sqsum, int le
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for( ; k < cn; k += 4 )
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{
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src = src0 + k;
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src = src0 + x * cn + k;
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ST s0 = sum[k], s1 = sum[k+1], s2 = sum[k+2], s3 = sum[k+3];
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SQT sq0 = sqsum[k], sq1 = sqsum[k+1], sq2 = sqsum[k+2], sq3 = sqsum[k+3];
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for( ; i < len; i++, src += cn )
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for(int i = x; i < len; i++, src += cn )
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{
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T v0, v1;
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v0 = src[0], v1 = src[1];
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